Saturday 18 August 2012

algebra quadratic equations

In the previous post we have discussed about Factoring Polynomials and In today's session we are going to discuss about algebra quadratic equations. In mathematics, algebra quadratic equations can be defined as an equation that has highest degree equals to 2. In other words it can be defined as an equation that has highest power is a square not more than two. If any expression has highest power more than 2 then it is not quadratic equation. Quadratic equation can be written as: pt2 + qt + r = 0. Formula to solve algebra quadratic expression is given as:

⇨ t = - b + √ (b2 – 4ac) / 2a.
Let’s talk about how to write a quadratic equation if roots value are known. Here we will follow some steps to write a quadratic equation.
Step 1: First of all we take two roots of an equation to write quadratic equation. Let we have two roots of an equation that is 5 and -7.
Step 2: Then we have to put roots in given form of q = (p - a) (p – b), here we put one root for variable ‘a’ and other root for next variable ‘b’. Put both roots in given form:
q = (p - a) (p – b), put a = 5 and b = -7,
So, it can be written as:
q = (p - 5) (p + 7),
Step 3: Multiply variable ‘p’ with all value of next pair and apply same procedure for second value. So it can be written as:
On multiplying we get:
q = (p - 5) (p + 7),
q = p2 + 7p – 5p – 35.
Step 4: Now we have to combine the same terms if present in equation otherwise this is required solution. So in above expression we have two like terms. On combining the equation we get:
q = p2 + 2p – 35. This is required quadratic form. (know more about Quadratic equation, here)

Rotational Kinetic Energy of a rigid body is found by first dividing kintic energy up into a collection of smaller masses. Before entering in 10 th board example please solve all cbse sample papers for class 10.

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