7th Grade Math

 In the previous post we have discussed about Free word problem solver and In today's session we are going to discuss about 7th Grade Math.

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7th grade math consists of many vital concepts that would be needed to solve higher grade math problems. Let us discuss the 7th grade math as follows:

1. Starting is done with a very basic conceptual understanding of numbers and mathematical operations. Numbers like rational numbers, the roots of perfect square, ratios and proportions, problems on percentages like profit – loss & discounts etc.

2. Learning the decimal numbers, conversion from fractions to decimals and vice – versa, comparison between different types of numbers etc.

3. Understanding scientific representation of numbers, problems involving surds & radicals, functions like absolute value, and also the idea of real numbers.

4. Operations that we learn are like addition, subtraction, multiplication and division of integers, fractions, decimals etc. Solving exponents, logarithms and properties related to them.

5. Learning the characteristics of numbers and using them in solving the maths problems related to algebra.

6. Next comes the geometrical maths which involves the understanding of the characteristics of angles and different shapes. Angles can be categorized as: Adjacent, Vertical, Linear, Complementary, Supplementary or Corresponding angles. Shapes or figures we learn like circles, lines, planes, polygons etc.

7. We learn to sketch the graphs of different figures on basis of their equations. Solving their equations and finding various parameters related to them. Understanding the behaviour of various functions (whether increasing, decreasing, inflection point, critical points etc.)

8. Learning the congruencies of triangles and solving the problems using different corollaries and well – defined theorems.

Let's see how to convert a decimal to a fraction?

A decimal has place values starting from tens place value. We remove the decimal and put number of zeros in front of one in the denominator according to the place values and then solve for the fraction. These concepts are detailed in iit sample papers.

Free word problem solver

In the previous post we have discussed about Seventh Grade Math and In today's session we are going to discuss about Free word problem solver. Mathematical word problem can be defined as a problem that are described in the form of narrative which are answered by converting them into corresponding computational form or in the form of equations. In simple terms we can say that a word problem is a problem which is written in word form and they are solved using mathematical properties. In mathematics, word problem basically deals with real world problems. There are two ways to defined to solve a math word problem that are given below:

A) First we need to convert the words in form of numerical equation or expression.

B) After that we can solve that problem very easily by applying mathematical rules.

Word problem solver free can be used for solving word problems. In school, most of students face difficulties while solving math word problem. To make student capable to successfully deal with these problems there are word problem solver available on Internet. These kinds of word problem solver provide their facility without charging any fees. Word problem solver free can be considered as sophisticated tool which is capable of solving any word problem by accepting problem from user and shows the answer in few seconds.

This kind of problem solver is very useful for those students who are beginners for solving math word problems. First describe the concept very clearly and carefully. After that solve the problem by generating the answer in step by step manner.

Math problem solver helps students to understand basic concepts and operations involved in word problem. In number system, irrational Number Examples include those examples that belong to concept of irrational numbers.

Next we will study Irrational Numbers Examples.

ICSE syllabus 2013 is available online, which can be downloaded for free.

Seventh Grade Math

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When we study Seventh Grade Math, we come across number system. In this chapter we will get the detailed knowledge about the types of numbers and their properties.

We start the concept with the study of the natural numbers. All the numbers which start from 1, 2, 3, 4, . . . . . . . . . upto infinite are called natural numbers. We say that the natural numbers are the counting numbers. We observe that each natural number has the successor , which we get by adding 1 to the given number. In the same way each natural number except 1 has a predecessor, which we get be subtracting 1 from the given number.

Now we come to the whole numbers. These numbers are used for measurement of the units. Thus we start whole numbers from 0. All the whole numbers have successors as natural numbers and leaving 0, each number has the predecessor too. Now we look at the Integers. Integers are the series of numbers which start from minus infinite and goes upto + infinite. All the numbers of the series can be expressed on the number line and we observe that the middle most number of the  series of integers in 0. Thus we say that the digits that exist on the right side of the  number 0 are positive numbers and the numbers which exist at the left side of the  number line are all negative numbers. Further we also observe that in the series of integers, all the numbers have their successor and the predecessors.

To learn about the  Measure Of Central Tendency, which is the topic of statistics, we can take help of math online tutors. It is the part of the curriculum of grade 8 of the Icse Syllabus 2013. 

Unit Circle

In the previous post we have discussed about one to one correspondence and In today's session we are going to discuss about Unit Circle. Unit Circle is defined as a circle that is having radius value is equal to 1. Let's us see the steps of making a this circle. Steps of making a circle is given as:

Step 1: To construct a circle it is very essential to have a radius value is equal to one always. If it is not so then it is not a unit circle.

Step 2: Now draw a tangent and solve equation with the help of Pythagoras theorem.

In mathematical geometry, Equation of circle (unit) is given by: i2 + j2 = 1, here ‘i’ plot the coordinate value along to x – axis and ‘j’ plot the coordinate value along to y – axis.

Now we will discuss the table based on circle. The table is shown below:

s.no	Ó¨ (rad)	Ó¨0	Sin Ó¨	Cos Ó¨	tanÓ¨ = sinÓ¨ / cos Ó¨
1	0 Л / 6	0 30	√0 / 2 = 0 √1 / 2 = 1 / 2	√4 / 2 = 1 √3 / 2	√0 / √4 = 0 √1 / √3 = √3 / 3
2	Л / 3	60	√3 / 2	√1 / 2 = 1 / 2	√3 / √1 = √3
3	Л / 2	90	√4 / 2 = 1	√0 / 2 = 0	----

Using these value we can solve any problem related to unit circle.

Some properties are also based on circle which are given as:

Distance assess from center of circle to any point on a circle is radius of circle. Radius is always half of diameter.

Line that is passing passes through center of circle is diameter of circle. Diameter of circle is always twice the radius value of circle.

Circumference – Formula to calculate circumference of circle is given by: Circumference of circle = 2 лR.

By using Properties of Multiplication we can easily solve the mathematical problems. cbse syllabus for class 9th 2013 is useful for class 9^th student.

one to one correspondence

In the previous post we have discussed about algebra quadratic equations and In today's session we are going to discuss about one to one correspondence. In this blog we will see discuss one to one correspondence. One – to – one correspondence is a process in which a condition in which elements of one set (Let a set A) can be properly (or evenly) matched with elements of second set (other set B). Here the meaning of this word evenly is each element of set 'A' relates to one and only one member of set 'B' and each element of set 'B' relates to one and only one member of set 'A'. It means each element of set 'A' is connect with exactly one element of set 'B' and vice versa. Now we will understand the detail of one to one correspondence. If we understand the terms of order pair (x, y) where 'x' is a element of set 'A' and 'y' is an element of set 'B'. Here two orders are not possible for this condition that has first element same and two order is not correct for same element. If this type of condition stable in a set than it shows one – to – one correspondence between sets A and B.

In other words, if two sets have same cardinality than one – to – one correspondence stable among two sets. Let’s have small introduction about one - to - one function. Basically one - to – one function is taken to check whether one – to – one correspondence stable among infinite sets.

Let's we have given a function and if function is one – to – one then one – to – one correspondence lie among the set of positive integers and set of odd positive integer. We can also calculate one – to – one correspondence between rational numbers and integer numbers, (any number represented as ratio of two whole numbers is called as rational number) but we can not calculate one – to – one correspondence among real numbers and integers.

Pythagorean Triples List contains with three positive integers p, q, and r, such that p² + q² = r². Before attempting the 12th board exam please solve cbse sample papers 12.

algebra quadratic equations

In the previous post we have discussed about Factoring Polynomials and In today's session we are going to discuss about algebra quadratic equations. In mathematics, algebra quadratic equations can be defined as an equation that has highest degree equals to 2. In other words it can be defined as an equation that has highest power is a square not more than two. If any expression has highest power more than 2 then it is not quadratic equation. Quadratic equation can be written as: pt² + qt + r = 0. Formula to solve algebra quadratic expression is given as:

⇨ t = - b + √ (b² – 4ac) / 2a.

Let’s talk about how to write a quadratic equation if roots value are known. Here we will follow some steps to write a quadratic equation.

Step 1: First of all we take two roots of an equation to write quadratic equation. Let we have two roots of an equation that is 5 and -7.

Step 2: Then we have to put roots in given form of q = (p - a) (p – b), here we put one root for variable ‘a’ and other root for next variable ‘b’. Put both roots in given form:

q = (p - a) (p – b), put a = 5 and b = -7,

So, it can be written as:

q = (p - 5) (p + 7),

Step 3: Multiply variable ‘p’ with all value of next pair and apply same procedure for second value. So it can be written as:

On multiplying we get:

q = (p - 5) (p + 7),

q = p² + 7p – 5p – 35.

Step 4: Now we have to combine the same terms if present in equation otherwise this is required solution. So in above expression we have two like terms. On combining the equation we get:

q = p² + 2p – 35. This is required quadratic form. (know more about Quadratic equation, here)

Rotational Kinetic Energy of a rigid body is found by first dividing kintic energy up into a collection of smaller masses. Before entering in 10 th board example please solve all cbse sample papers for class 10.

Factoring Polynomials

In mathematics, any expressions which is join with constants, variables and exponent values is said to be polynomial expression. And also polynomial expression is join with together by mathematical operators like (+, -, *, /). Infinite values are not taken in case of polynomials expression. For example: 12xy² – 4x + 7y³ – 20, this given equation is polynomial equation, in this equation exponents values are 0, 1, 2 and 3. Negative and fraction values are also taken in case of polynomial expression. It is not joined with together by division operator.

Let’s discuss that how to solve Factoring Polynomials. Here we will understand the quadratic to calculate polynomial expressions.

Let we have a polynomial expression 2p² + 4p – 10, we can factorize this polynomial as shown below:

We will find its factor by quadratic formula. Formula to find factors is given by:

P = -b + √ (b² - 4ac) / 2a, here value of 'a' is 2, value of 'b' is 4 and value of 'c' is -10. So put these values in formula. On putting these values we get:

P = - 4 + √ [(4)² - 4(2) (-10)] / 2(2); on moving ahead we get,

P = - 4 + √ (16 + 80) / 4, we can also write it as,

P = - 4 + √ (96) / 4. So, here we get two factor of this expression, one positive and other negative.

P = -4 + √ 24 and P = -4 - √ 24.

These two are factors of above expression. With the help of quadratic formula formula we can find factors of any polynomial expression. (know more about Factoring Polynomials, here)

Rotational Inertia can be defined as the moment of inertia that must be specified with respect to a selected axis of rotation. It is also said to be moment of inertia. icse board papers 2013 is useful for 2013 exam point of view.